Optimal. Leaf size=136 \[ \frac {a e^2 x}{d^3}-\frac {b e^2 x}{d^3}+\frac {b e x^2}{4 d^2}-\frac {b x^3}{9 d}+\frac {b e^2 x \log (c x)}{d^3}-\frac {e x^2 (a+b \log (c x))}{2 d^2}+\frac {x^3 (a+b \log (c x))}{3 d}-\frac {e^3 (a+b \log (c x)) \log \left (1+\frac {d x}{e}\right )}{d^4}-\frac {b e^3 \text {Li}_2\left (-\frac {d x}{e}\right )}{d^4} \]
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Rubi [A]
time = 0.11, antiderivative size = 136, normalized size of antiderivative = 1.00, number of steps
used = 8, number of rules used = 7, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.333, Rules used = {269, 45, 2393,
2332, 2341, 2354, 2438} \begin {gather*} -\frac {b e^3 \text {PolyLog}\left (2,-\frac {d x}{e}\right )}{d^4}-\frac {e^3 \log \left (\frac {d x}{e}+1\right ) (a+b \log (c x))}{d^4}-\frac {e x^2 (a+b \log (c x))}{2 d^2}+\frac {x^3 (a+b \log (c x))}{3 d}+\frac {a e^2 x}{d^3}+\frac {b e^2 x \log (c x)}{d^3}-\frac {b e^2 x}{d^3}+\frac {b e x^2}{4 d^2}-\frac {b x^3}{9 d} \end {gather*}
Antiderivative was successfully verified.
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Rule 45
Rule 269
Rule 2332
Rule 2341
Rule 2354
Rule 2393
Rule 2438
Rubi steps
\begin {align*} \int \frac {x^2 (a+b \log (c x))}{d+\frac {e}{x}} \, dx &=\int \left (\frac {e^2 (a+b \log (c x))}{d^3}-\frac {e x (a+b \log (c x))}{d^2}+\frac {x^2 (a+b \log (c x))}{d}-\frac {e^3 (a+b \log (c x))}{d^3 (e+d x)}\right ) \, dx\\ &=\frac {\int x^2 (a+b \log (c x)) \, dx}{d}-\frac {e \int x (a+b \log (c x)) \, dx}{d^2}+\frac {e^2 \int (a+b \log (c x)) \, dx}{d^3}-\frac {e^3 \int \frac {a+b \log (c x)}{e+d x} \, dx}{d^3}\\ &=\frac {a e^2 x}{d^3}+\frac {b e x^2}{4 d^2}-\frac {b x^3}{9 d}-\frac {e x^2 (a+b \log (c x))}{2 d^2}+\frac {x^3 (a+b \log (c x))}{3 d}-\frac {e^3 (a+b \log (c x)) \log \left (1+\frac {d x}{e}\right )}{d^4}+\frac {\left (b e^2\right ) \int \log (c x) \, dx}{d^3}+\frac {\left (b e^3\right ) \int \frac {\log \left (1+\frac {d x}{e}\right )}{x} \, dx}{d^4}\\ &=\frac {a e^2 x}{d^3}-\frac {b e^2 x}{d^3}+\frac {b e x^2}{4 d^2}-\frac {b x^3}{9 d}+\frac {b e^2 x \log (c x)}{d^3}-\frac {e x^2 (a+b \log (c x))}{2 d^2}+\frac {x^3 (a+b \log (c x))}{3 d}-\frac {e^3 (a+b \log (c x)) \log \left (1+\frac {d x}{e}\right )}{d^4}-\frac {b e^3 \text {Li}_2\left (-\frac {d x}{e}\right )}{d^4}\\ \end {align*}
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Mathematica [A]
time = 0.05, size = 125, normalized size = 0.92 \begin {gather*} \frac {36 a d e^2 x-36 b d e^2 x+9 b d^2 e x^2-4 b d^3 x^3+36 b d e^2 x \log (c x)-18 d^2 e x^2 (a+b \log (c x))+12 d^3 x^3 (a+b \log (c x))-36 e^3 (a+b \log (c x)) \log \left (1+\frac {d x}{e}\right )-36 b e^3 \text {Li}_2\left (-\frac {d x}{e}\right )}{36 d^4} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 0.07, size = 211, normalized size = 1.55
method | result | size |
risch | \(\frac {a \,x^{3}}{3 d}-\frac {a e \,x^{2}}{2 d^{2}}+\frac {a \,e^{2} x}{d^{3}}-\frac {a \,e^{3} \ln \left (d x +e \right )}{d^{4}}+\frac {b \,x^{3} \ln \left (c x \right )}{3 d}-\frac {b \,x^{3}}{9 d}-\frac {b e \,x^{2} \ln \left (c x \right )}{2 d^{2}}+\frac {b e \,x^{2}}{4 d^{2}}+\frac {b \,e^{2} x \ln \left (c x \right )}{d^{3}}-\frac {b \,e^{2} x}{d^{3}}-\frac {b \,e^{3} \dilog \left (\frac {c d x +c e}{e c}\right )}{d^{4}}-\frac {b \,e^{3} \ln \left (c x \right ) \ln \left (\frac {c d x +c e}{e c}\right )}{d^{4}}\) | \(168\) |
derivativedivides | \(\frac {\frac {a \,c^{3} e^{2} x}{d^{3}}-\frac {a \,c^{3} e \,x^{2}}{2 d^{2}}+\frac {a \,c^{3} x^{3}}{3 d}-\frac {a \,c^{3} e^{3} \ln \left (c d x +c e \right )}{d^{4}}+\frac {b \,c^{3} x^{3} \ln \left (c x \right )}{3 d}-\frac {b \,c^{3} x^{3}}{9 d}-\frac {b \,c^{3} e \,x^{2} \ln \left (c x \right )}{2 d^{2}}+\frac {b \,c^{3} e \,x^{2}}{4 d^{2}}+\frac {b \,c^{3} e^{2} x \ln \left (c x \right )}{d^{3}}-\frac {b \,c^{3} e^{2} x}{d^{3}}-\frac {b \,c^{3} e^{3} \dilog \left (\frac {c d x +c e}{e c}\right )}{d^{4}}-\frac {b \,c^{3} e^{3} \ln \left (c x \right ) \ln \left (\frac {c d x +c e}{e c}\right )}{d^{4}}}{c^{3}}\) | \(211\) |
default | \(\frac {\frac {a \,c^{3} e^{2} x}{d^{3}}-\frac {a \,c^{3} e \,x^{2}}{2 d^{2}}+\frac {a \,c^{3} x^{3}}{3 d}-\frac {a \,c^{3} e^{3} \ln \left (c d x +c e \right )}{d^{4}}+\frac {b \,c^{3} x^{3} \ln \left (c x \right )}{3 d}-\frac {b \,c^{3} x^{3}}{9 d}-\frac {b \,c^{3} e \,x^{2} \ln \left (c x \right )}{2 d^{2}}+\frac {b \,c^{3} e \,x^{2}}{4 d^{2}}+\frac {b \,c^{3} e^{2} x \ln \left (c x \right )}{d^{3}}-\frac {b \,c^{3} e^{2} x}{d^{3}}-\frac {b \,c^{3} e^{3} \dilog \left (\frac {c d x +c e}{e c}\right )}{d^{4}}-\frac {b \,c^{3} e^{3} \ln \left (c x \right ) \ln \left (\frac {c d x +c e}{e c}\right )}{d^{4}}}{c^{3}}\) | \(211\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.33, size = 146, normalized size = 1.07 \begin {gather*} -\frac {{\left (\log \left (d x e^{\left (-1\right )} + 1\right ) \log \left (x\right ) + {\rm Li}_2\left (-d x e^{\left (-1\right )}\right )\right )} b e^{3}}{d^{4}} - \frac {{\left (b \log \left (c\right ) + a\right )} e^{3} \log \left (d x + e\right )}{d^{4}} + \frac {4 \, {\left (3 \, a d^{2} + {\left (3 \, d^{2} \log \left (c\right ) - d^{2}\right )} b\right )} x^{3} - 9 \, {\left ({\left (2 \, d \log \left (c\right ) - d\right )} b + 2 \, a d\right )} x^{2} e + 36 \, {\left (b {\left (\log \left (c\right ) - 1\right )} + a\right )} x e^{2} + 6 \, {\left (2 \, b d^{2} x^{3} - 3 \, b d x^{2} e + 6 \, b x e^{2}\right )} \log \left (x\right )}{36 \, d^{3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A]
time = 126.33, size = 253, normalized size = 1.86 \begin {gather*} \frac {a x^{3}}{3 d} - \frac {a e x^{2}}{2 d^{2}} - \frac {a e^{3} \left (\begin {cases} \frac {x}{e} & \text {for}\: d = 0 \\\frac {\log {\left (d x + e \right )}}{d} & \text {otherwise} \end {cases}\right )}{d^{3}} + \frac {a e^{2} x}{d^{3}} + \frac {b x^{3} \log {\left (c x \right )}}{3 d} - \frac {b x^{3}}{9 d} - \frac {b e x^{2} \log {\left (c x \right )}}{2 d^{2}} + \frac {b e x^{2}}{4 d^{2}} + \frac {b e^{3} \left (\begin {cases} \frac {x}{e} & \text {for}\: d = 0 \\\frac {\begin {cases} - \operatorname {Li}_{2}\left (\frac {d x e^{i \pi }}{e}\right ) & \text {for}\: \frac {1}{\left |{x}\right |} < 1 \wedge \left |{x}\right | < 1 \\\log {\left (e \right )} \log {\left (x \right )} - \operatorname {Li}_{2}\left (\frac {d x e^{i \pi }}{e}\right ) & \text {for}\: \left |{x}\right | < 1 \\- \log {\left (e \right )} \log {\left (\frac {1}{x} \right )} - \operatorname {Li}_{2}\left (\frac {d x e^{i \pi }}{e}\right ) & \text {for}\: \frac {1}{\left |{x}\right |} < 1 \\- {G_{2, 2}^{2, 0}\left (\begin {matrix} & 1, 1 \\0, 0 & \end {matrix} \middle | {x} \right )} \log {\left (e \right )} + {G_{2, 2}^{0, 2}\left (\begin {matrix} 1, 1 & \\ & 0, 0 \end {matrix} \middle | {x} \right )} \log {\left (e \right )} - \operatorname {Li}_{2}\left (\frac {d x e^{i \pi }}{e}\right ) & \text {otherwise} \end {cases}}{d} & \text {otherwise} \end {cases}\right )}{d^{3}} - \frac {b e^{3} \left (\begin {cases} \frac {x}{e} & \text {for}\: d = 0 \\\frac {\log {\left (d x + e \right )}}{d} & \text {otherwise} \end {cases}\right ) \log {\left (c x \right )}}{d^{3}} + \frac {b e^{2} x \log {\left (c x \right )}}{d^{3}} - \frac {b e^{2} x}{d^{3}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {x^2\,\left (a+b\,\ln \left (c\,x\right )\right )}{d+\frac {e}{x}} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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